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3 years ago

the square and the equilateral triangle at the right have the same perimeter find the lengths of the sides of the triangle

1 answer:

5 0

The square and the equilateral triangle at the right have the same perimeter.Find the length of the sides of the triangle. One side of the triangle has 3x and the square has a side. Algebra -> Test -> SOLUTION: The square and the equilateral triangle at the right have the same perimeter.

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Pond A and Pond B have 20 fishes altogether.

-Dominant- [34]

Answer:

Step-by-step explanation:

a+b+b+c+a+c=58

2a+2b+2c=58

divide by 2

a+b+c=29

3 0

3 years ago

Hi <img src="https://tex.z-dn.net/?f=789456123%20%5Cdiv%20321654987" id="TexFormula1" title="789456123 \div 321654987" alt="7

denpristay [2]

Answer:

≈2.45436

Step-by-step explanation:

I typed it in my calculator.

6 0

3 years ago

Can someone pls help me . ASAPPP

STALIN [3.7K]

Volume without holes = 3 x 6 x 11 = 198 cubic inches.

Calculate volume of one hole:

3.14 x 0.5^2 x 3 = 2.355 cubic inches

There are 3 holes: 3 x 2.355 = 7.065

Subtract volume of the holes from the brick:

198 - 7.065 = 190.935 cubic inches.

Rounded to the nearest tenth: 190.9 cubic inches.

8 0

3 years ago

Read 2 more answers

Jose deposits S300 into an account that pays simple interest at a rate of 6% per year. How much interest will he be paid in the

Readme [11.4K]

Answer:

$54

Step-by-step explanation:

300 times 0.06 times 3

0.06 times 3 = 0.18

300 times 0.18 = 54

The simple interest is $54

5 0

3 years ago

Read 2 more answers

Find dy/dx when y = Ln (sinh 2x). A. 2 cosh 2x B. 2 sech 2x C. 2 coth 2x D. 2 csch 2x

givi [52]

The function given is a composite function. Let's work from the outside in:
$y=(ln(sinh(2x)))$

First step:
$\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]$

Now, let's work it out:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * \frac{d}{dx}[sinh(2x)]$

Next step:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) * \frac{d}{dx}[2x]$

Next step:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *2$

Simplify:
$\frac{dy}{dx} = \frac{2cosh(2x)}{sinh(2x) }$

Simplify further:
$\frac{dy}{dx} = 2 (\frac{cosh(2x)}{sinh(2x)})$

Remember that:
${\frac{cosh(x)}{sinh(x)} = coth(x)$

So, your final answer is:
$\boxed{ \frac{dy}{dx} = 2coth(2x) }$

So, your answer is C. Hope I could help you!

8 0

4 years ago