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3 years ago

Please help me I will give brainlest if right

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

6 0

Given:

Consider the given polynomial is:

$x^3+4x^2+16x+64$

To find:

The complete factorization of the given polynomial.

Solution:

We have,

$x^3+4x^2+16x+64$

Using grouping method, we get

$=(x^3+4x^2)+(16x+64)$

$=x^2(x+4)+16(x+4)$

$=(x+4)(x^2+16)$

$=(x+4)(x+4i)(x-4i)$ $[\because x^2+y^2=(x+iy)(x-iy)]$

Therefore, the correct option is C.

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2 years ago

Use the commutative property for addition to rearrange the algebraic expression 5x-7y-8x+y

BartSMP [9]

You want to use the addition property, so you need to ADD each term. Just change the minuses to pluses, making sure you keep the negative with the number

5x-8x-7y+y =

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3 years ago

How do you solve this?

puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let $x$ represent the width.

Since the length is 7 feet longer, we can represent the length by $x+7$ .

Now that we have our values for the length and the width we can multiply them together to find our area.

$(x)(x+7)=x^{2} +7x$

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

$(x+7)(x+14)$

And multiply our area by 3.

$3(x^{2} +7x)$

set these equal to each other to find your new equation.

$(x+7)(x+14)=3(x^{2} +7x)$

Now you need to solve for $x$ . To do this first muliply $(x+7)$ and $(x+14)$ .

$(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98$

Then multiply $3(x^{2} +7x)$

$3(x^{2} +7x)=\\3x^{2} +21x$

Now you can begin solving for $x$ .

$x^{2} +21x+98=3x^{2} +21x$

Subtract $x^{2}$ from both sides.

$21x+98=2x^{2} +21x$

Subtract $21x$ from both sides.

$98=2x^{2}$

Divide by 2.

$49=x^{2}$

And finally take the sqaure root of both sides.

$\sqrt{x^{2} }=\sqrt{49}\\x=7$

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of $x$ , we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0

3 years ago

0.357 round to 2 decimal places

Andrej [43]

.36. Just put that in

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3 years ago

Read 2 more answers