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1 answer:

5 0

Y=mx+b
m=slope
b=yint

slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given
(-1,3) and (2,-3)
slope=(-3-3)/(2-(-1))=(-6)/(2+1)=-6/3=-2

y=2x+b
find b
(-1,3) is a point
when x=-1, y=3
3=2(-1)+b
3=-2+b
add 2
5=b

y=2x+5

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In AQRS OR=7, RS=11 M<=42 IN AUVT VT=26, TU= 44 M

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I think the answer to In AQRS OR=7, RS=11 M<=42 IN AUVT VT=26, TU= 44 M is THE TRIANGLES ARE NOT SIMILAR.

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3 years ago

Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$