The limit is x---->4-
The negative show that x approaches from the left
Now
As x approaches 4 from the left ... Means This number should be less than 4 (<4) but really close to 4.
Let's pick a Number
Say 3.99
Substitute this... You have
3.99/3.99-4
3.99/-0.01
If we choose x to be 3.999
we will have
3.999/-0.001
Notice the pattern... As x approaches 4 from the left... This limit will approach NEGATIVE INFINITY
Why?
As you approach 4 from the left... 3.9,3.99,3.999... You notice that the denominator becomes negative and EXTREMELY SMALL... and when you divide by an extremely small Number..... You'll get a relatively HUGE VALUE(You can try this... Use a calc... Divide any number of choice by a very small number... say.. 0.0000001.... You'll get a huge result
In our case... The denominator is negative... So it Will Approach a very Huge Negative Number
Hence
Answer.. X WILL APPROACH NEGATIVE INFINITY.
Vertical asymptotes are the zeroes of the denominator of a function
The denom. is x-4
Equate to zero to get the asymptote
x-4=0
x=4
Hence... There will be a vertical asymptote at x=4.
Have a great day!
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
Answer:
The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.
Step-by-step explanation:
A confidence interval has the following format.
In which 
is the mean of the sample and M is the margin of error.
In this problem, we have that:
The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.
Answer:
He ran 11,420 miles on the weekend.
Step-by-step explanation:
It's simple: add 4610 and 6810 to get 11,420
hope this helped!
The image point of (4,-2) after the transformations given is; (2,1).
<h3>What is the image point after the transformations?</h3>
It follows from the task content that the point given is (4, -2) which first reflects over the y axis and hence, renders the new image to be; (4, 2) after which it undergoes a dilation of with dilation factor, 1/2 and hence, the image point is; (2,1).
Read more on transformations;
brainly.com/question/2689696
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