Answer:
$4
Step-by-step explanation:
2/100 x 200 = 4
notice that, if Q is the midpoint of PR, that simply means that PQ = QR = 43.
![\bf \boxed{P}\underset{\leftarrow 9x-31 \to }{\stackrel{\stackrel{\downarrow }{43}}{\rule[0.35em]{10em}{0.25pt}}Q\stackrel{43}{\rule[0.35em]{10em}{0.25pt}}}\boxed{R} \\\\\\ 9x-31=43+43\implies 9x-31=86\implies 9x=117 \\\\\\ x=\cfrac{117}{9}\implies x=13](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7BP%7D%5Cunderset%7B%5Cleftarrow%209x-31%20%5Cto%20%7D%7B%5Cstackrel%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7B43%7D%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7DQ%5Cstackrel%7B43%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%7D%5Cboxed%7BR%7D%0A%5C%5C%5C%5C%5C%5C%0A9x-31%3D43%2B43%5Cimplies%209x-31%3D86%5Cimplies%209x%3D117%0A%5C%5C%5C%5C%5C%5C%0Ax%3D%5Ccfrac%7B117%7D%7B9%7D%5Cimplies%20x%3D13)
Answer:
x= 6, -6
Step-by-step explanation:
Answer:
a) positive direction: t < 2s & t>6s ; negative direction: 2s < t < 6s
b) 7 m
c) 71 m
Step-by-step explanation:
Given:
v(t) = 3t^2 -24t +36 [0 , 7]
Find:
a) The value of time when particle is moving in positive direction:
The change in direction of the particle can be determined by v(t) > 0
Hence,
0 < 3t^2 -24t +36
0 < t^2 - 8t + 12
0 < (t - 2)*(t - 6)
t < 2s , t > 6s
The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.
b) The displacement ds over the given interval [ 0 , 7 ]
ds = integral (v(t)).dt
ds = t^3 -12t^2 +36t
ds = 7^3 -12*7^2 +36*7
ds = 7 m
c) Total distance traveled in the interval:
Total distance= ds(0-2) + ds(2-6) + ds(6-7)
D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7
D = 2*32 - 2*0 + 7
D = 71 m
60 Add both then divide by 2 and thats what you will get
