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3 years ago

What is the solution to the system of equations?

2 answers:

6 0

Substitution would be a great approach to solving this system, because the first equation defines y as x - 10 and you can thus substitute x - 10 for y in the second equation:

2x + (x - 10) = 4

Then 3x - 10 = 4, and 3x = 14. Solving for x: x = 14/3.

Since y = x-10, subst. 14/3 for x to find y: y = 14/3 - 30/3 = -16/3

The solution is (14/3, -16/3).

AnnZ [28]3 years ago

4 0

Answer: (6, -8)

Step-by-step explanation:

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3 years ago

A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

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Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

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4 years ago