2(m - 5) + 6PEMDASu multiply 2 into (m-5)2*m and 2*-5that would be 2m-10 + 6now subtract common variables-10 + 6 = -42m - 4
Answer:#1- 3.0 in. #2- 11.0 in.
Step-by-step explanation:
The correct answer would be b. range. you take the largest amount and subtract the smallest amount giving you the range.
Let x and y be the 2 parts of 15 ==> x + y=15 (given)
Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)
Let's solve 1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)
==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy
But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50
Now we have the sum S of the 2 parts that is S = 15 and
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
Answer:
8,64,216,512
Step-by-step explanation:
