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yarga [219]
1 year ago
12

Can u help me with my math I’m confused and don’t know

Mathematics
1 answer:
Aneli [31]1 year ago
3 0

We want to find the area of the rectangle.

The area of a rectangle is given by;

\text{Area}=\text{Length x Breadth}

The length is x + 7 and the breadth is given by x + 5.

Thus the area is;

\begin{gathered} A=(x+7)(x+5) \\ A=x^2+7x+5x+35 \\ A=x^2+12x+35 \end{gathered}

Therefore, the area is;

A=x^2+12x+35

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If (x+2) is a factor of x^3-6x^2+kx+10, k=
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5 0
4 years ago
If x-2 is a factor of x^2+3x+k, what is the value of k?
Ne4ueva [31]
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3 years ago
Let f(x) = x^2 + 4x - 31. for what value of a is there exactly one real value of x such that f(x) = a?
allsm [11]
This value of "a" is exactly the y-coordinate of the vertex of the parabola
y = x%5E2+%2B+4x++-+31.

To find it, complete the square:

x%5E2+%2B+4x++-+31 = %28x%2B2%29%5E2+-+4+-+31 = %28x%2B2%29%5E2+-+35.

So, this value of "a" is a = -35.










Figure. Plot y = x%5E2+%2B+4x++-+31.


5 0
3 years ago
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