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liq [111]
2 years ago
5

Find the value of x. 8:5 = 1/x:1

Mathematics
1 answer:
tatiyna2 years ago
5 0

Answer:x=61

Step-by-step explanation​

 

856−5x3{131}=2

8(x−9)+5(5−18)+1(15−6x)=2

8x−72−65+15−6x=2

2x=122

x=61

sorry if i'm wrong

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If I owe you $1.76 in overtime pay, you receive $19.50 for each hour of OT. How many hours overtime are you owed?
Lady_Fox [76]

Answer: 0.09 hours

Step-by-step explanation:

You are owed $1.76 in overtime pay.

The hourly rate for overtime is $19.50 per hour.

To find the number of hours owed, you need to divide the amount owed by the amount owed per hour.

The number of hours you are owed is therefore:

= Amount owed / Amount owed per hour

= 1.76 / 19.50

= 0.09 hours

6 0
3 years ago
1.
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

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4 0
3 years ago
7x − 5 &lt; 13x − 3 <br><br>PLz anyone
Ksju [112]

7x-5<13x-3

Minus 7x

-5<6x-3

then add 3

-2<6x

Then divide -2 by 6 and 6x by 6

-1/3>x

I think thats right

4 0
3 years ago
PLEASE HELP ASAP I'M TIMED
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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which expression represents the number 2i4−5i3+3i2+−81‾‾‾‾√ rewritten in a+bi form?
vichka [17]

Answer:

The expression -1+14i represents  the number 2i^4-5i^3+3i^2+\sqrt{-81} rewritten in a+bi form.

Step-by-step explanation:

The value of i is i=\sqrt{-1}[tex] or [tex]i^{2}=-1[\tex].Now [tex]i^{4} in term of i^{2}[\tex] can be written as, [tex]i^{4}=i^{2}\times i^{2}

Substituting the value,

i^{4}=\left(-1\right)\times \left(-1\right)

Product of two negative numbers is always positive.

\therefore i^{4}=1

Now i^{3} in term of i^{2}[\tex] can be written as, [tex]i^{3}=i^{2}\times i

Substituting the value,

i^{3}=\left(-1\right)\times i

Product of one negative  and one positive numbers is always negative.

\therefore i^{3}=-i

Now \sqrt{-81} can be written as follows,

\sqrt{-81}=\sqrt{\left(81\right)\times\left(-1\right)}

Applying radical multiplication rule,

\sqrt{ab}={\sqrt{a}}\sqrt{b}

\sqrt{\left(81\right)\times\left(-1\right)}={\sqrt{81}}\sqrt{-1}

Now, \sqrt{\left(81\right)=9 and \sqrt{-1}}=i

\therefore \sqrt{\left(81\right)\times\left(-1\right)}=9i

Now substituting the above values in given expression,

2i^4-5i^3+3i^2+\sqrt{-81}=2\left(1\right)-5\left(-i\right)+3\left(-1\right)+9i

Simplifying,

2+5i-3+9i

Collecting similar terms,

2-3+5i+9i

Combining similar terms,

-1+14i

The above expression is in the form of a+bi which is the required expression.

Hence, option number 4 is correct.

5 0
3 years ago
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