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3 years ago

Physical science is

Physics

1 answer:

zimovet [89]3 years ago

5 0

Physical science is the study of matter and energy, and the relationship between matter and energy.

E. The study of matter and energy, and the relationship between matter and energy

<u>Explanation:</u>

The study of issue and vitality and the associations between physicists concentrate such subjects as gravity, light, and time. Albert Einstein, a well known physicist, built up the Theory of Relativity.

Material science is the investigation of issue and vitality at all scales—from the littlest particles of the issue to the whole universe.

A geologist has practical experience throughout the entire existence of Earth. A sea-life scholar contemplates sea plants and creatures. A physicist ponders matter, vitality, and how they are connected.

There are three primary parts of science: physical science, Earth science, and life science. Physical science is the investigation of lifeless common items and the laws that administer them. It incorporates material science, science, and cosmology.

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A 98-kg fullback is running along at 8.6 m / s when a 76-kg defensive back running in the same direction at 9.8 m / s jumps on h

algol13

The total momentum before and after the collision must be conserved.

The total momentum before the collision is:
$p_i = m_1 v_1 + m_2 v_2$
where m1 and m2 are the masses of the two players, and $v_1$ and $v_2$ their initial velocities. Both are considered with positive sign, because the two players are running toward the same direction.

The final momentum is instead
$p_f = (m_1+m_2)v_f$
because now the two players are moving together with a total mass of (m1+m2) and final speed vf.

By requiring that the momentum is conserved
$p_i=p_f$
we can calculate vf, the post-collision speed:
$m_1 v_1 + m_2 v_2 = (m_1+m_2)v_f$
$v_f = \frac{m_1 v_1 + m_2 v_2}{m_1 +m_2}= \frac{(98 kg)(8.6 m/s)+(76 kg)(9.8m/s)}{98 kg+76 kg}=9.1 m/s$
and the direction is the same as the direction of the players before the collision.

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3 years ago

How is the levitation of the SCMagLev train achieved? Just write a sentence.

Harman [31]

Answer:

<h2>The SCMaglev (superconducting maglev, formerly called the MLU) is a magnetic levitation (maglev) railway system developed by Central Japan Railway Company (JR Central) and the Railway Technical Research Institute</h2>

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2 years ago

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Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (

alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b) $E_1=\dfrac{\sigma}{\epsilon_0}$

c) $E_2=\dfrac{\sigma}{\epsilon_0}$

Explanation:

Let $\sigma$ be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

$E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}$

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

$E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0$

b)The Electric Field to the right of the sheets

$E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}$

c)The Electric Field to the left of the sheets

$E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}$

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3 years ago

A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.64 10-2 kg/s. the density of the gasoline is 735

Irina18 [472]

Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m

Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²

Let v = speed of pumping the gasoline, m/s
Then the mass flow rate is
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s

The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s

Answer: 2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.

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3 years ago

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An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/

Katen [24]

<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

$y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}$ (1)