The liquid that will evaporate the quickest would be water.
<em>~The rest are mixtures, and have more ingrediants in them, therefore the answer should be water. (in which it has no other ingrediants in it but water itself)</em>
Answer:
Option C is the correct answer
Explanation:
Distance travelled by car during reaction time
![=15\times0.4\\\\=6m](https://tex.z-dn.net/?f=%3D15%5Ctimes0.4%5C%5C%5C%5C%3D6m)
The car stopped before hitting the animal by ![1 m](https://tex.z-dn.net/?f=1%20m)
Distance travelled during deceleration is ![21-6-1=14m](https://tex.z-dn.net/?f=21-6-1%3D14m)
Hence by ![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
We have
![0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2](https://tex.z-dn.net/?f=0%5E2%3D15%5E2%2B2%20%5Ccdot%20a%20%5Ccdot%2014%5C%5C%5C%5Ca%3D%5Cfrac%7B-225%7D%7B28%7D%20%5C%5C%5C%5C%3D-8.03m%2Fs%5E2)
Option C is the correct answer
The boat’s resultant velocity with respect to North is determined as 17 m/s.
<h3>Resultant velocity of the boat</h3>
The boat’s resultant velocity with respect to North is calculated as follows;
R² = Va² + Vb²
R = √(Va² + Vb²)
R = √(15² + 8²)
R = 17 m/s
Thus, the boat’s resultant velocity with respect to North is determined as 17 m/s.
Learn more about resultant velocity here: brainly.com/question/24767211
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Answer
Give that,
mass of two student m = 3.10 kg
distance from the axis of the rotation is r = 1 m
angular speed ω = 0.754 rad /s
moment of inertia I = 3.10 kg m²
position from the rotation of the axis is r_1 = 0.29 m
Total moment of inertia I ' = I + 2 m r²
= 3.1 +2 x 3.1 x( 1)^2
= 9.3 kg m²
moment of inertia inward horizontally from the position of rotation axis is
I" = I + 2 m r^2
= 3.1 + 2 * 3.1 kg ( 0.29)^2
= 3.62 kg m^2
a ) new angular speed is ω_1 =![\dfrac{I'\omega}{I''}](https://tex.z-dn.net/?f=%5Cdfrac%7BI%27%5Comega%7D%7BI%27%27%7D)
=
= 1.94 rad /s
b ) K.E before the system pulls weight inward is
![K.E = \dfrac{1}{2} I' \omega^2](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20I%27%20%5Comega%5E2)
![K.E = \dfrac{1}{2}\times 9.3 \times 0.754^2](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.3%20%5Ctimes%200.754%5E2)
![K.E =2.64\ J](https://tex.z-dn.net/?f=K.E%20%3D2.64%5C%20J)
c )K.E after the system pulls weight inward is
![K.E = \dfrac{1}{2} I'' \omega_1^2](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%20I%27%27%20%5Comega_1%5E2)
![K.E = \dfrac{1}{2}\times 3.62 \times 1.92^2](https://tex.z-dn.net/?f=K.E%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%203.62%20%5Ctimes%201.92%5E2)
![K.E =6.67\ J](https://tex.z-dn.net/?f=K.E%20%3D6.67%5C%20J)
Answer:
x rays is the correct answer