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Ksivusya [100]
3 years ago
13

Simplify to create an equivalent expression -y minus -3(-3y+5)

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

8y-15

Step-by-step explanation:

-y-3(-3y+5)

-y+9y-15

8y-15

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What Is the answer to 1/6 + 2/3<br>​
arlik [135]

Answer:

5/6

Step-by-step explanation:

When adding fractions, you must ensure the denominator is the same in both fractions.

In this case, the 3 can be multiplied by 2 to equal 6, the other denominator.

When multiplying fractions to create a common denominator, you must multiply the both the numerator and the denominator by the same value, to ensure that the fraction is still equivalent.

2/3 × 2/2 = (2×2)/(3×2) = 4/6

Replace 2/3 with its equivalent 4/6.

Now you will add the numerators together.

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Ryanne is 14. Her brother’s age is three more than half her age. How old is her brother?
tamaranim1 [39]

Answer:

10

Step-by-step explanation:

14 / 2=7

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

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d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

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Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

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