60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
Answer:
80
Step-by-step explanation:
8+6^2×2
8 + 36 × 2
8+72
80
Answer:
The number of wrapping paper sold was 32 and the number of magazines sold was 40
Step-by-step explanation:
Let
x ----> the number of wrapping paper sold
y ----> the number of magazines sold
we know that
The classes sold 72 items
so
----> equation A
The classes earned $222 for their school
so
----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is (32,40)
see the attached figure
therefore
The number of wrapping paper sold was 32 and the number of magazines sold was 40
Answer:
C
Step-by-step explanation:
Because for a quadratic formula to be applicable..., x must be to the power of two(x^2)
