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love history [14]

3 years ago

13

In 1998, a 2,505 gallon ice cream float was made in Atlanta, Georgia. How many 1 pint servings did the float contain? Please hel

p, this is the last question on my homework. Thank you!

1 answer:

8_murik_8 [283]3 years ago

3 0

1 pint equal to 16 oz now divide 2505 to 16 = to 156 so it contain 156 pints of gallons

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PLEASE HELP I WILL MAKE BRAINLIEST

juin [17]

Answer:

m∠T = 79°

m∠V = 14°

Step-by-step explanation:

Given

m∠T = (2x + 85)°

m∠V = (5x + 29)°

As the sum of measures of the angles is 93°.

so

m∠T + m∠V = 93°

(2x + 85)° + (5x + 29)° = 93°

Remove parentheses

$2x+85+5x+29=93$

$7x+114=93$

Subtract 114 from both sides

$7x+114-114=93-114$

Simplify

$7x=-21$

Divide both sides by 7

$\frac{7x}{7}=\frac{-21}{7}$

simplify

$x=-3$

Determining m∠T

m∠T = (2x + 85)°

substitute x = -3

m∠T = (2(-3) + 85)°

= -6 + 85

= 79°

Thus, we conclude that m∠T = 79°

Determining m∠V

m∠V = (5x + 29)°

substitute x = -3

m∠T = (5(-3) + 29)°

= -15 + 29

= 14°

Thus, we conclude that m∠V = 14°

<u>VERIFICATION:</u>

m∠T + m∠V = 93°

substitute m∠T = 79° and m∠V = 14°

79° + 14° = 93°

93° = 93°

L.H.S = R.H.S

5 0

3 years ago

PLEASE HELP !!ASAP

Ulleksa [173]

<u>Answer:</u>

6x-5y=-10

<u>Step-by-step explanation:</u>

We are given an equation in words and we are to translate it and then re-write its standard form:

<em>'y space equals space 6 over 5 x space plus space 2 '</em>

$y = \frac { 6 } { 5 } x + 2$

Re-arranging this given equation to get:

$y - 2 = \frac { 6 } { 5 } x$

$5(y-2)=6x$

$5y-10=6x$

$6x-5y=-10$

So the correct answer option is 6x-5y=-10.

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3 years ago

Which of these equations is in POINT-SLOPE form?

goblinko [34]

Y-3=23(x-4) hope this helps

7 0

3 years ago

Write the number in standard form.<br><br> 7×10^7

mamaluj [8]

7×10^7 = 70000000 (10^7 = 10000000)

4 0

4 years ago

Read 2 more answers

Find the probability for the experiment of tossing a coin three times. Use the sample space S = {HHH, HHT, HTH, HTT, THH, THT, T

myrzilka [38]

Answer:

1) 0.375

2) 0.375

3) 0.5

4) 0.5

5) 0.875

6) 0.5

Step-by-step explanation:

We are given the following in the question:

Sample space, S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}.

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

1. The probability of getting exactly one tail

P(Exactly one tail)

Favorable outcomes ={HHT, HTH, THH}

$\text{P(Exactly one tail)} = \dfrac{3}{8} = 0.375$

2. The probability of getting exactly two tails

P(Exactly two tail)

Favorable outcomes ={ HTT,THT, TTH}

$\text{P(Exactly two tail)} = \dfrac{3}{8} = 0.375$

3. The probability of getting a head on the first toss

P(head on the first toss)

Favorable outcomes ={HHH, HHT, HTH, HTT}

$\text{P(head on the first toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

4. The probability of getting a tail on the last toss

P(tail on the last toss)

Favorable outcomes ={HHT,HTT,THT,TTT}

$\text{P(tail on the last toss)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

5. The probability of getting at least one head

P(at least one head)

Favorable outcomes ={HHH, HHT, HTH, HTT, THH, THT, TTH}

$\text{P(at least one head)} = \dfrac{7}{8} = 0.875$

6. The probability of getting at least two heads

P(Exactly one tail)

Favorable outcomes ={HHH, HHT, HTH,THH}

$\text{P(Exactly one tail)} = \dfrac{4}{8} = \dfrac{1}{2} = 0.5$

3 0

3 years ago