How to expand and evaluate

If ST=19 and S lies at -4 , where could T be located?

Natasha2012 [34]

Answer:

15 or -23

Step-by-step explanation:

I think you probably already turned this in but in case you haven't:

ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?

So there's two directions we could go.

Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)

But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)

Please mark as Brainliest! :)

8 0

2 years ago

The circumference of a circular garden is 84 feet. What is the diameter of the garden

swat32

Diameter is 25.46 feet as circumference is 2πr and 2r is d so we just simply divide the circumference with π and get the value as 25.46

Step-by-step explanation:

6 0

1 year ago

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Evaluate the following question PLZ

kozerog [31]

Answer:

1599995904

Step-by-step explanation:

first, you must do the top part of the fraction. you can start by doing the power numbers such as 2 power 4, 4 power 6 and 4 power 4.

the complete answer for the top part is: 12x 16x 4069x 8x 2x 256 which equals: 3199991808

then, you must divide by 2 which gives you the answer of: 1599995904

8 0

2 years ago

Write the equation using function notation f(x). then find f(0) 2x^2 - 3y = 6

Grace [21]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f(0) = -2$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6$

$\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2}$

$\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6$

$\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3}$

$\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

[ here, y can be replaced with f(x) because y is a function of x ]

$\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2$

$\large\textsf{Find f(0):}$

$\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2$

$\qquad \tt \rightarrow \: f(0) = 0 - 2$

$\qquad \tt \rightarrow \: f(0) = - 2$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

1 year ago

Solve the system by substitution. 6x + 3y = -6 2x + y = -2

Mariana [72]

Solutions

First Lets solve for this equation $6x + 3y = -6
$

$6x + 3y = -6
$

$6x+3(-2-2x)=-6

 
$

$-6=-6$

Therefore this given equation is a dependent system.

Solve for $2x + y = -2$

$2x+y=-2$

$y=-2-2x

 

 
$

There are too many solutions to these equations.

8 0

3 years ago

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