F(C) = 9/5C + 32
I'll just change F(C) to y and 9/5C to 9/5x.
y = 9/5x + 32
inverse...
x = 9/5y + 32
9/5y = x - 32
y = 5/9x - 160/9
Sooooo
F(C) = 5/9C - 160/9
A. 100/20
The distance in meters should be divided by the time in seconds to get the value of the distance in meters travelled in one second.
They are opposite exterior angles