Answer:
Given: In parallelogram ABCD, AC=BD
To prove : Parallelogram ABCD is rectangle.
Proof : in △ACB and △BDA
AC=BD ∣ Given
AB=BA ∣ Common
BC=AD ∣ Opposite sides of the parallelogram ABCD
△ACB ≅△BDA∣SSS Rule
∴∠ABC=∠BAD...(1) CPCT
Again AD ∥ ∣ Opposite sides of parallelogram ABCD
AD ∥BC and the traversal AB intersects them.
∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is
180∘
From (1) and (2) ,
∠BAD=∠ABC=90∘
∴∠A=90∘ and ∠C=90∘
Parallelogram ABCD is a rectangle.
Answer:
8x+y-13=0
Step-by-step explanation:
let the given point be
A(1,5)=(x1,y1)
slope(m)= -8
then,equation of straight line is,
(y-y1)=m(x-x1)
(y-5)= -8(x-1)
y-5= -8x+8
8x+y-5-8=0
therefore,8x+y-13=0 ..........(i) is the required equation.
To find the decimal form, you have to manually divide 1 by 8. Since 8 is greater than 1, the quotient would then start with 0., then you add a 0 next to 1, to make it 10. This time, divide 10 by 8. The nearest answer would be 1, because 1 *8 = 8. Subtracting this from 10, you get 2. Add another 0 to 2, to make it 20. Do the cycle all over again. The complete solution is as follows:
0.125
---------------------------
8 | 10
- 8
------------------------
20
-16
-------------
40
- 40
-------------
0
<em>Hence, the decimal form of 1/8 is 0.125.</em>
Answer:
C - 10
Step-by-step explanation:
n is the number of the term
an = -2n+8
a9 = -2*9 +8
a9 = -18+8
a9 = -10
The 9th term is -10
