The equation would be x<5
First, graph the line x=5
Then, to determine which side of the line to shade, use a test point. I like (0,0). I plug in 0 for x because that is the x value. 0 does make the equation correct so (0,0) is included inside the shaded area. Shade the side that has (0,0) in it and you're done.
A=p (1+I/k)^kn
A future value 160000
p present value ?
I interest rate 6/100=0.06
K compounded semiannual 2
T time 18-7=11years
160000=p (1+0.06/2)^(2×11)
Divide each side by (1+0.06/2)^(2×11)
P=160,000÷(1+0.06÷2)^(2×11)
P=83,502.8
Hope it helps:-)
let x be the first integer
x+ 2 the second integer ( two consecutive even )
smaller integer added to three times the larger <span>x + 3 ( x+2)
</span>two less than five times the smaller <span>5x - 2</span>
x + 3 ( x+2) = 5x - 2
x+3x +6 = 5x -2
x=8
the first integer = 8
the second is x+2 =10
If the ratio of girls to boys in Mr. Hansen's class is 4:5, and the ratio of girls to boys in Ms. Luna's class is 8:10, then the equation that correctly compares the ratio of both Mr. Hansen's class and Ms. Luna's class are 4/5 = 8/10.
