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4 years ago

Math question please help

Mathematics

1 answer:

Volgvan4 years ago

7 0

let coordinates be (x , y)

Calculate x coordinate :- (x + 1) / 2 = -6 gving x = -13

y coordinate:- (y + 3)/2 = -5 giving y = y = -13

Its choice B

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In circle R with m angle QRS= 90 and QR= 3 units find the length of arc QS round to the nearest hundredth

Advocard [28]

Answer:

4.71 units

Step-by-step explanation:

The formula for arc length =

2πr × θ/360

From the above question,

r = QR = 3 units

θ = angle QRS= 90 = 90°

The length of the arc is calculated as:

2 × π × 3 × 90/360

= 4.7123889804 units

Approximately to the nearest hundredth = 4.71 units

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3 years ago

A rectangular shaped desk has a length of 25 inches and a width of 18 inches. A desk with a similar shape has a length of 60 inc

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3 years ago

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Phantasy [73]

Answer:

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2nd Box: $5*3-25$

3rd Box: $(25-5)*3$

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2 years ago

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A functiom is graphed on the coordinate plane.<br><br>What is the value of the function when x=4?

Elena L [17]

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3 years ago

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From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle

Mariulka [41]

Answer:

30.11 meters ( approx )

Step-by-step explanation:

Let x be the distance of a point P ( lies on the building ) from the top of the building such that AP is perpendicular to the building and y be the distance of the building from point A, ( shown in the below diagram )

Given,

Point A is 8.20 m above level ground,

So, the height of the building = ( x + 8.20 ) meters,

Now, 1 degree = 60 minutes,

⇒ $1\text{ minute } =\frac{1}{60}\text{ degree }$

$20\text{ minutes }=\frac{20}{60}=\frac{1}{3}\text{ degree}$

$50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}$

By the below diagram,

$tan ( 12^{\circ} 50') = \frac{8.20}{y}$

$tan(12+\frac{5}{6})^{\circ}=\frac{8.20}{y}$

$tan (\frac{77}{6})^{\circ}=\frac{8.20}{y}$

$\implies y=\frac{8.20}{tan (\frac{77}{6})^{\circ}}$

Now, again by the below diagram,

$tan (31^{\circ}20')=\frac{x}{y}$

$tan(31+\frac{1}{3})=\frac{x}{y}$

$\implies x=y\times tan(\frac{94}{3})=\frac{8.20}{tan (\frac{77}{6})^{\circ}}\times tan(\frac{94}{3})^{\circ}=21.9142943216\approx 21.91$

Hence, the height of the building = x + 8.20 = 30.11 meters (approx)

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3 years ago