Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Lamar used 80% of his data, so he used a greater percentage.
Answer:
B. y = -1/2x
Step-by-step explanation:
Because the answer is in point-slope intercept form, we know -1/2 is m. Also, because the equation is setting y equal to x, we know it goes through the origin.
IT IS 15 BECAUSE YOU HAVE TO ADD IT UP
= 6x + 6x - 6x × 7 + 6xy - 7y
36x2 - 42x + 6xy - 7y
