To find f(3), plug x = 3 in f(x),
∴ f(3) = 3(3)+1 = 9+1 = 10
Therefore, the ordered pair is (3,10)
For second one,
plug x = 10 in f⁻¹(x),
f⁻¹(10) = 10-1/3 = 9/3 = 3
Therefore, the ordered pair is (10,3)
Step-by-step explanation:
first one c/a
second one b/a
Answer:
here you go
Step-by-step explanation:
1 is = 2 is >
Answer
Length = 10 ft
Width = 5 ft
Explanation
Area of the rectangle given = 50 ft²
Let the width of the rectangle be x
So this means the length of the rectangle will be 3x - 5
What to find:
The dimensions of the rectangle.
Step-by-step solution:
Area of a rectangle = length x width
i.e A = L x W
Put A = 50, L = 3x - 5, W = x into the formula.
The quadratic equation can now be solve using factorization method:
Since the dimension can not be negative, hence the value of x will be = 5.
Therefore, the dimensions of the rectangle will be:
Answer:
a:c = 35:24
a:c = 20:27
a:c = 35:22
a:c = 28:27
Step-by-step explanation:
a:b = 7:3
Using cross products
3a = 7b
Divide by 7
3a/7 = b
Now we want
8b = 5c
Substitute in 3a/7 for b
8 (3a/7) = 5c
24/7a = 5c
Multiply by 7
24/7a *7 = 5*7c
24a = 35c
Divide by c
24 a/c = 35
Divide by 24
a/c = 35/24
a:c = 35:24
a:b = 4:9
Using cross products
9a = 4b
Divide by 4
9a/4 = b
Now we want
3b = 5c
Substitute in 9a/4 for b
3 (9a/4) = 5c
27/4a = 5c
Multiply by 4
27/4a *4 = 5*4c
27a = 20c
Divide by c
27 a/c = 20
Divide by 27
a/c = 20/27
a:c = 20:27
b:c = 5:11
Using cross products
11b = 5c
Divide by 11
b = 5c/11
Now we want
2a = 7b
Substitute in 5c/11 for b
2a = 7(5c/11)
2a = 35c/11
Multiply by 11
2a*11 = 35c
22a = 35c
Divide by c
22 a/c = 35
Divide by 22
a/c = 35/22
a:c = 35:22
b:c = 14:3
Using cross products
3b = 14c
Divide by 3
b = 14c/3
Now we want
9a = 2b
Substitute in 14c/3 for b
9a = 2(14c/3)
9a = 28c/3
Multiply by 3
9a*3 = 28c
27a = 28c
Divide by c
27 a/c = 28
Divide by 27
a/c = 28/27
a:c = 28:27
