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4 years ago

What are two numbers that when multiplied equal 54, and also when added equals -15

1 answer:

6 0

6 x -9 = -54
6 + (-9) = -3

x2 - 3x - 54 = 0

(X + 6 ) (X - 9)

x2 - 3x - 54 = (X + 6 ) (X - 9)
=
6 & -9

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Let x be the certain number and that six time this number may be expressed as 6x. Based on the conditions presented above, the sum of 6x and 8 should be equal to 32. This may be mathematically expressed as,

6x + 8 = 32

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3 years ago

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<h3>The equivalent expression is:</h3>

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Solution:

Given expression is:

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}$

We have to find the equivalent expression

We can simplify the above expression using law of exponents

Use the following law of exponents:

$a^m \times a^n = a^{m+n}$

Therefore,

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}$

Use another law of exponent

$(a^m)^n = a^{mn}$

Therefore,

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

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