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Citrus2011 [14]
3 years ago
6

Please help!! i have limited time

Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:

tnhjhjjhhhhhhhhhhhhhhhh

Step-by-step explanation:nbbn

jhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Phantasy [73]3 years ago
5 0

Answer:

Number 1

Step-by-step explanation:

The median in number 1 is 13 and the range for number 1 is also thirteen so it has to be it.

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Number sentences for these 4?
Murrr4er [49]
A. 15-35=-20
b. -2+7=5
c. -10+14=4
d. 60-100=-40
6 0
3 years ago
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
3 years ago
PLZ HELP ME I NEED HELP AND FAST ⚠️
Liula [17]

Answer:

Yor awnser is C and D.

Step-by-step explanation:

6 0
3 years ago
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What is 27/33 is the lowest term?
MariettaO [177]
9/11

Hope this helps
6 0
3 years ago
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Find the interval in which the function is positive x^2-x-6=y
Semmy [17]

Answer:

(-INFINITY , -2) (3 , INFINITY)

Function is positive when above the x axis

Function is below the x axis between -2 and 3

6 0
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