Question

How many units long is a segment whose endpoints are (-4,1) and (1,13)?

Answer 1

Answer:

D = 13

Step-by-step explanation:

We'll find its length using Distance Formula:

Distance Formula = $\sqrt{(x2-x1)^2+(y2-y1)^2}$

D = $\sqrt{(1+4)^2+(13-1)^2}$

D = $\sqrt{(5)^2+(12)^2}$

D = $\sqrt{25+144}$

D = $\sqrt{169}$

D = 13

Answer 2

Answer:

13

Step-by-step explanation:

(1−−4)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(1++0)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(5)2+(12)2‾‾‾‾‾‾‾‾‾‾‾√25+144‾‾‾‾‾‾‾‾‾√169‾‾‾‾√≈13

Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

Hope this helps!!! PLZ MARK BRAINLIEST!!!