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Rainbow [258]
3 years ago
12

How many units long is a segment whose endpoints are (-4,1) and (1,13)?

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Answer:

D = 13

Step-by-step explanation:

We'll find its length using Distance Formula:

Distance Formula = \sqrt{(x2-x1)^2+(y2-y1)^2}

D = \sqrt{(1+4)^2+(13-1)^2}

D = \sqrt{(5)^2+(12)^2}

D = \sqrt{25+144}

D = \sqrt{169}

D = 13

Ann [662]3 years ago
7 0

Answer:

13

Step-by-step explanation:

(1−−4)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(1++0)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(5)2+(12)2‾‾‾‾‾‾‾‾‾‾‾√25+144‾‾‾‾‾‾‾‾‾√169‾‾‾‾√≈13

Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

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Which of the following expressions could represent the total amount withdrawn from Brandon’s checking account during the time pe
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The Solution:

Given:

Each withdrawal by Brandon = $x

ATM charge per transaction = $2

Required:

To find an expression for Brandon's total withdrawal if he withdraws the same amount once a week for 7 weeks.

Step 1:

We shall find the total amount of each withdrawal, that is, the sum of the amount withdrawn and the ATM charge for the transaction.

\text{ Each withdrawal=x+2=\$(x+2)}

Step 2:

Finding the required total amount, we have:

\text{ Total amount withdrawn=7(x+2)=\$7(x+2)}\begin{gathered} 7(x+2) \\ or \\ 7x+14 \\ \text{ or} \\ 7\mleft(x\mright)+7\mleft(2\mright) \end{gathered}

Therefore, the correct answers are: [options 2, 3, and 4]

6 0
1 year ago
Find the value of 3x³+2x²-4 at x=2​
Virty [35]

Answer:

3(2) cube+2(2) square-4

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A wheel has a radious of 50cm. How many times would the wheel go around if it rolled for 10km
Zinaida [17]
First you must make sure all measurements are in the same value: You can choose either cm or km

Distance = 1,000,000 cm or 10 km

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2 years ago
The density of a fluid is given by the empirical equation rho=70.5 exp(8.27 X 10^-7 P) where rho is density (lbm/ft^3) and P is
jasenka [17]

Answer:

(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf

(b) density = 0.1206g/cm^3

(c) rho = 0.1206exp(8.27×10^-7P)

Step-by-step explanation:

(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf

(b) P = 9×10^6N/m^2

rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3

rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3

(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is

rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)

5 0
3 years ago
Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = \frac{p x_{2}+q x_{1}}{p+q}

y = \frac{p y_{2}+q y_{1}}{p+q}

From the question

x_{1} = 2

x_{2} = ?

x = 4

y_{1} = -1

y_{2} = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = \frac{p x_{2}+q x_{1}}{p+q}

4 = \frac{1(x_{2})+4(2) }{1+4}

4 = \frac{x_{2}+8}{5}

x_{2} + 8 = 20

x_{2} = 12

Also

y = \frac{p y_{2}+q y_{1}}{p+q}

1 = \frac{y_{2}+4(-1)}{5}

y_{2} - 4 = 5

y_{2} = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

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3 years ago
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