Question

The length of a rectangle is 6 yd longer than its width. if the perimeter of the rectangle is 44 yd , find its area.

Answer 1

Let's call the length L and the width w. 

perimeter = 2L + 2w
44 = 2L + 2w

the length is 6 yards longer than the width. so L = w + 6.

plug this into the equation. 44 = 2(w+6) + 2w
44 = 2w + 12 + 2w
44 = 4w + 12
32 = 4w
w = 8
L = w + 6
L = 8 + 6
L = 14

area = Lw
area = 8(14)
area = 112 yd²