The length of a rectangle is 6 yd longer than its width. if the perimeter of the rectangle is 44 yd , find its area.
1 answer:
Let's call the length L and the width w.
perimeter = 2L + 2w
44 = 2L + 2w
the length is 6 yards longer than the width. so L = w + 6.
plug this into the equation. 44 = 2(w+6) + 2w
44 = 2w + 12 + 2w
44 = 4w + 12
32 = 4w
w = 8
L = w + 6
L = 8 + 6
L = 14
area = Lw
area = 8(14)
area = 112 yd²
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Step-by-step explanation:
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9v-v=16
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v=16/8
v=2
Is it number 21 you need help with?
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use Pythagorean Theorem to satisfy...a^2 + b^2 = c^2
200^2 + b^2 = 300^2
b^2 = 300^2 - 200^2
b^2 = 50000 (get square root of each)
b = 223.606 (rounded to the nearest tenth.... = 223.6
