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Salsk061 [2.6K]
2 years ago
12

Ryan and Sheila are preparing to get married. Sheila has a car payment of $297.00 per month, which is 9% of her monthly income.

After they are married, Sheila knows that her car payment will only be 5% of their combined monthly income. How much money does Ryan make per month?
Mathematics
1 answer:
netineya [11]2 years ago
5 0

Answer:

$2640

Step-by-step explanation:

Sheila's car payment is 9% of her total income.

let i = total income

this equation can be used to represent the information :

9%  x i = $297

to determine i, divide both sides of the equation by 9%

$297 / 0.09 = $3300

After the marriage, the car payment which is 3300 would be 5% of the combined income.

let c = combined income

5% x c = $297

c = $297 / 0.05 = $5940

Ryan's income = combined income - Sheila's income

$5940 - $3300 = $2640

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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
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Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

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So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

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MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

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n (E) = favorable outcomes

N = Total number of outcomes.

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P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

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The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

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P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

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Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

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