All categories

2 years ago

the fastest train in the us can travel 2.6 miles per minute.At that speed how far does it go in half an hour?

2 answers:

8 0

The train good 2.6 miles in a minutes and you are looking for how far it does in 30 minutes you have multiply 30 times 2.6 and you get 78 miles
30•2.6 = 78

Readme [11.4K]2 years ago

4 0

You have to multiply 2.6 × 30=
$2.6 \times 30 =78.0$

You might be interested in

Let sin(−θ)=−3/5 and tanθ>0. What is the value of cos(−θ)?

Jobisdone [24]

Answer:

The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ .

Step-by-step explanation:

Given Trigonometric function as :

sin( - Ф ) = $\frac{- 3}{5}$

- sin Ф = $\frac{- 3}{5}$

So, sin Ф = $\frac{ 3}{5}$

Now, as sin Ф = $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$

So , $\dfrac{\textrm perpendicular}{\textrm hypotenuse}$ = $\frac{ 3}{5}$

So, perpendicular = 3

And hypotenuse = 5

Now,<u> From Pythagoras Theorem</u>

Base ² = Hypotenuse² - Perpendicular²

Or, Base ² = 5² - 3²

Or, Base ² = 25 - 9

Or, Base ² = 16

∴ Base = $\sqrt{16}$

I.e Base = 4

Now, Cos Ф = $\dfrac{\textrm base}{\textrm hypotenuse}$

So, Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Now , Since

Cos ( - Ф ) = Cos Ф

So, Cos ( - Ф ) = Cos Ф = $\dfrac{\textrm 4}{\textrm 5}$

Hence The value of Cos (-Ф) $\dfrac{\textrm 4}{\textrm 5}$ . Answer

6 0

2 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$