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ExtremeBDS [4]
3 years ago
5

Does the KE of a car change more when it goes from 10 to 20 km/h or when it goes from 20 to 30 km/h?

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0
<h2>The change in KE is more for speed change from 20 to 30 km/h</h2>

Step-by-step explanation:

Let the mass of car be m.

Speed change from 10 to 20 km/h.

     Initial speed = 10 km/hr

     Initial KE = 0.5 x m x 10² = 50 m

     Final speed = 20 km/hr

     Final KE = 0.5 x m x 20² = 200 m

     Change in KE = 200m - 50m = 150m

Speed change from 20 to 30 km/h.

     Initial speed = 20 km/hr

     Initial KE = 0.5 x m x 20² = 150 m

     Final speed = 30 km/hr

     Final KE = 0.5 x m x 30² = 450 m

     Change in KE = 450m - 200m = 250m

The change in KE is more for speed change from 20 to 30 km/h

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Excuse me I need more information to solve this question.

Step-by-step explanation:

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Talia sells educational software for a yearly salary of $65,000 plus a 2.65% commission on her total sales. If Talia sells $2.5
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Answer:

$131250

Step-by-step explanation:

Talia's earnings during one year are equal to her base yearly salary ($65000) added to her commission. Now, to know the commission it is necessary to find the 2.65% of her total sales ($2.5 million)

Step 1. Divide the total sales or 2,500,000 by 100 considering this represents the total or 100%

2,500,000 ÷ 100 = 25000

Step 2. Multiply this number by the specific percentage (2.65)

25000 x 2.65 = 66250

Now add the commission and the yearly salary

65000 + 66250 = 131250

Hence, total earnings of Talia were $131250

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3 years ago
Isaac played a video game 20 times and wont about 70% of the games. how many games did he win
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Hello!

We know that Isaac played 20 games and won about 70% of them. Now, we must find what 70% of 20 is, so that we know how many games Isaac won.

First, convert the percentage to a decimal by dividing it by 100.

70% ÷ 100 = 0.70

Next, multiply the total amount of games Isaac played (20) by about how many he won (0.70):

20 × 0.70 = 14

ANSWER:

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Triangle ABC is similar to triangle PQR, as shown below:
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Answer:

\frac{q}{b}=\frac{r}{c}

Step-by-step explanation:

Consider the options for this question are as follow,

  • \frac{q}{c}=\frac{r}{b}
  • \frac{c}{p}=\frac{b}{a}
  • \frac{c}{a}=\frac{q}{r}
  • \frac{q}{b}=\frac{r}{c}

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

\traingle ABC\sim \triangle PQR

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}

\frac{c}{r}=\frac{a}{p}=\frac{b}{q}

\frac{r}{c}=\frac{p}{a}=\frac{q}{b}

\implies \frac{q}{b}=\frac{r}{c}

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