All categories

3 years ago

А

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

Answer:

Helppppppp Neeeeeeeeded asapppppp

Step-by-step explanation:

You might be interested in

Two figures are shown. EFJL is dialation of ABIK AB has a length of 12 and EF has a length of 3

Dimas [21]

The scale factor of dilation from AB to EF is 0.25

<h3>How to determine the scale factor of dilation?</h3>

The given parameters are:

EFJL is dilation of ABIK
AB has a length of 12
EF has a length of 3

From the above parameters, side lengths AB and EF are corresponding sides

This means that:

The scale factor of dilation (k) is

k = AB/EF

So, we have

k = 3/12

Evaluate

k = 0.25

Hence, the scale factor of dilation from AB to EF is 0.25

Read more about scale factors at:

brainly.com/question/15891755

#SPJ1

4 0

1 year ago

Which partial quotients could be added to find 396 ÷ 12?

Travka [436]

Answer:

33 plz braniest i think i help you

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

PUZZLE: six wolves catch six lambs in six minutes. How many wolves will be needed to catch sixty lambs in sixty minutes?

Korolek [52]

Six i think cause it take each wolf 6 minutes to catch a lamb so it should still be six

4 0

3 years ago

In the library at Lenape Elementary School, there are 3/8

antoniya [11.8K]

Your answer is 163⁄<span>200 i thinks because if this is adding yeah</span>

6 0

3 years ago

Read 2 more answers

Show all work and reasoning

Natalija [7]

Split up the interval [2, 5] into $n$ equally spaced subintervals, then consider the value of $f(x)$ at the right endpoint of each subinterval.

The length of the interval is $5-2=3$ , so the length of each subinterval would be $\dfrac3n$ . This means the first rectangle's height would be taken to be $x^2$ when $x=2+\dfrac3n$ , so that the height is $\left(2+\dfrac3n\right)^2$ , and its base would have length $\dfrac{3k}n$ . So the area under $x^2$ over the first subinterval is $\left(2+\dfrac3n\right)^2\dfrac3n$ .

Continuing in this fashion, the area under $x^2$ over the $k$ th subinterval is approximated by $\left(2+\dfrac{3k}n\right)^2\dfrac{3k}n$ , and so the Riemann approximation to the definite integral is

$\displaystyle\sum_{k=1}^n\left(2+\frac{3k}n\right)^2\frac{3k}n$

and its value is given exactly by taking $n\to\infty$ . So the answer is D (and the value of the integral is exactly 39).

8 0

3 years ago