Question

JK has endpoints J(13,8) and K(-6,-6). Find the coordinates of the midpoint of JK

Answer 1

Answer:

$\left(\dfrac{7}{2},\ 1\right)$

Step-by-step explanation:

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

We have the points J(13, 8) and K(-6, -6).

Substitute:

$M_{JK}=\left(\dfrac{13+(-6)}{2},\ \dfrac{8+(-6)}{2}\right)=\left(\dfrac{7}{2},\ \dfrac{2}{2}\right)=\left(\dfrac{7}{2},\ 1\right)$

Answer 2

Answer: This is accomplished by averaging the x and y coordinates.

So the midpoint's x coordinate is found as (13+-6)/2 = 3.5

Similarly, the y coordinate is (8+-6)/2 = 1

So the point is (3.5,1)

Step-by-step explanation: