Alright, this is simple. You know what the new number is, 54. You know the original number was decreased by 40%. Your looking for the original number, X. So set up an equation.
x-.4x=54
When X stands by itself, it's perceived to value 1.00
1.00-.4x=54
(1.00-.4 [40%]=.6)
.6x=54
Divide both sides by .6 to eliminate everything else.
.6x/.6=54/.6
You get 90. Your original number was indeed 90.
To check it, we can do 90/40%, or 90/.4=54
~Hope this helps!
Option a. 1/4 is the right answer
Step-by-step explanation:
Given expression is:

Here
we know that
a = x
In order to find the number which should be added
comparing with the formula


So, we will add the square of 1/2 which is 1/4
Hence,
Option a. 1/4 is the right answer
Keywords: Expressions, polynomials
Learn more about polynomials at:
#LearnwithBrainly
Answer:
8,630
Step-by-step explanation:




Answer:


Step-by-step explanation:
<u>Inequalities
</u>
The home security company will choose between two options for cubicles: the small cubicle for only one operator and the large cubicle to hold 2 operators. Let x be the number of small cubicles and y the number of large cubicles. Since each small cubicle has 49 square feet, the total area occupied by them will be 49x. Each large cubicle occupies 80 square feet, so the y cubicles use 80y square feet. The total area used by them is
Area=49x+80y
Assuming there is no operator without cubicle and all cubicles are fully occupied, the number of operators will be
Operators=1x+2y=x+2y
The number of cubicles is
# cubicles=x+y
The conditions of the problem state that


Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Let x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.

Multiply both sides by 100.


Divide both sides by 50.


The amount invested at 7% is
.
The amount invested at 8% is

The amount invested at 9% is

Thus, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.