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4 years ago

If ABCD ~ EHFG what do you know about the corresponding sides? Be specific.

Mathematics

1 answer:

melomori [17]4 years ago

6 0

The answer for this is the last option

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In a class there are 20 boys and 15 girls.The ratio of boys to girls is

BigorU [14]

Answer:

can u explain more and if not i thnk it is 20:15

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. What is the lateral surface area of the label of the

Soloha48 [4]

Answer:

$52\pi \text{ cm}^2\approx 162.11\text{ cm}^2$

Step-by-step explanation:

We have been given that a label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. We are asked to find the lateral surface area of the label of the soup can in square centimeters.

We will use lateral surface area of cylinder to solve our given problem as:

$LA=2\pi rh$ , where,

r = Radius of cylinder,

h = height of cylinder.

Upon substituting our given values in above formula, we will get:

$LA=2\pi \times\text{4.3 cm}\times \text{6 cm}$

$LA=51.6\pi \text{ cm}^2$

$LA=162.10618\text{ cm}^2$

Therefore, the lateral surface area of the label of the soup is approximately 162.11 square cm.

5 0

4 years ago

Read 2 more answers

The beverage orders for a school cafeteria are shown in the graph. If 760 students purchase a beverage with their lunch, how man

snow_tiger [21]

Answer:

B)114

Step-by-step explanation:

15 percent of 760 is 114

3 0

4 years ago

Read 2 more answers

Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B

Tems11 [23]

Answer:

0.75

Step-by-step explanation:

Given,

P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,

P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,

Where,

A = event that the selected student has a Visa card,

B = event that the selected student has a MasterCard,

C = event that the selected student has an American Express card,

We know that,

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)

= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07

= 0.75

Hence, the probability that the selected student has at least one of the three types of cards is 0.75.

5 0

3 years ago

7 with tiny 2 on top-9+1 with little 3 on top

olga2289 [7]

Your answer would be 41... I hope this helps :D

5 0

3 years ago