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3 years ago

Help please answer these question

Mathematics

1 answer:

yawa3891 [41]3 years ago

8 0

Answer:

#3. d = -10.25

Step-by-step explanation:

#3. d = -6.5 + -3.75

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A bag contians 15 navy and 26 violet marbles.Amarbleis drawn at random.What is the theoretiacl probttly of drwaing a violet marb

telo118 [61]

Answer:26/41

Step-by-step explanation:

Cause 15 plus 26 =41 Hope this was helpful :)

8 0

3 years ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

Nevaeh went shopping for a new phone because of a discount sale. She multiplied the price of the phone by 0.95 to find the price

ella [17]

Answer:

95% off

Step-by-step explanation:

because the percent u times by the actual price is the percent u have off

3 0

3 years ago

Write an equation in slope-intercept form from the linear inequality graphed in the picture.

stepladder [879]

Answer:

equation: y = x+3
inequality: y < x+3

Step-by-step explanation:

The slope of the line is 1 unit of rise for 1 unit of run, so ...

m = rise/run = 1/1 = 1

The y-intercept is 3 grid lines above the x-axis, so is (0, 3).

Then the equation of the line is ...

y = 1x +3

The inequality has that line as a boundary, but the y-values on the line are not part of the solution space. Only y-values below the line (less than those on the line) are in the solution. The inequality is ...

y < x +3

3 0

3 years ago

16 is what percent of 50?

vovikov84 [41]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers