Show that if y=x^2 + 8x - 3 then y> -19 for all values of x

Mathematics

2 answers:

Alex777 [14]4 years ago

8 0

X^2+8x-3>-19 l+19
x^2+8x+16<0

x^2+4x+4x+16<0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
please my answer!!!!

algol134 years ago

4 0

X^2+8x-3>-19 | +19
x^2+8x+16>0

x^2+4x+4x+16>0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
this is true cause (X+4)^2 >0 cause X+4>0

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