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4 years ago

Show that if y=x^2 + 8x - 3 then y> -19 for all values of x

Mathematics

2 answers:

Alex777 [14]4 years ago

8 0

X^2+8x-3>-19 l+19
x^2+8x+16<0

x^2+4x+4x+16<0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
please my answer!!!!

algol134 years ago

4 0

X^2+8x-3>-19 | +19
x^2+8x+16>0

x^2+4x+4x+16>0
x(x+4)+4(x+4)>0
(x+4)(x+4)^2>0
this is true cause (X+4)^2 >0 cause X+4>0

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I am being timed pls asap

DiKsa [7]

Answer:

Writing it in matrix form

- 2 - 4 - 5 - 155

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I hope this helps you

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4 years ago

Is (1,8) a solution to this system of equations? 19x+3y=2 3x+y=11

pantera1 [17]

Answer:

No (1,8) is not a solution to 19x+3y=2.

However, (1,8) is a solution to 3x+y=11.

Step-by-step explanation:

(1,8)

The one represents the x shown in each equation, the eight represents the y.

Substitute the one in for the x and the eight in for the y.

19x+3y=2

19(1)+3(8)

3x+y=11

3(1)+(8)

Next, solve the equation.

19(1)+3(8) = 43

3(1)+(8) = 11

As you can see, 43 does not equal 2.

But, 11 does equal 11.

7 0

2 years ago

Given the conditional statement ~p -> q which statement is logically equivalent?

icang [17]

Any implication is logically equivalent to its contrapositive. In other words,

¬p ⇒ q ⇔ ¬q ⇒ p

(¬ means the same thing as ~, "not")

To prove this: recall that

p ⇒ q ⇔ ¬p ∨ q

This is because p ⇒ q is true if p is false, or both p and q are true, i.e.

p ⇒ q ⇔ ¬p ∨ (p ∧ q)

Disjunction (∨ or "or") distributes over conjunction (∧ or "and"), so that

p ⇒ q ⇔ (¬p ∨ p) ∧ (¬p ∨ q)

but ¬p ∨ p is always true, or a tautology, so we're just left with ¬p ∨ q.

Then

¬p ⇒ q ⇔ p ∨ q

… ⇔ q ∨ p

… ⇔ ¬(¬q) ∨ p

… ⇔ ¬q ⇒ p

4 0

3 years ago

How can you explain that 1/2 is larger than 1/4?

garri49 [273]

Answer:

1/2 is bigger

Step-by-step explanation

1/2 means it was split in 2 pieces

1/4 means it was split in four pieces

3 0

3 years ago

Read 2 more answers

Find x. Round your answer to the nearest tenth of a degree. x

NeTakaya

Answer:

x ≈ 48.2°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{9}$ , then

x = $cos^{-1}$ ( $\frac{6}{9}$ ) ≈ 48.2° ( to the nearest tenth )

5 0

3 years ago