Answer:
\log_{b}({b^x})=x
Step-by-step explanation:
hope this helps
Answer:
48 sir
Step-by-step explanation:
Answer: Option B.
Step-by-step explanation:
We know that her living room has the shape of a rectangle and its dimensions on the floor plan are:
by ![2\ \frac{1}{2}\ in](https://tex.z-dn.net/?f=2%5C%20%5Cfrac%7B1%7D%7B2%7D%5C%20in)
We can convert from mixed numbers to decimal numbers:
![1\ \frac{7}{8}\ in=(1+0.875)\ in=1.875\ in](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B7%7D%7B8%7D%5C%20in%3D%281%2B0.875%29%5C%20in%3D1.875%5C%20in)
![2\ \frac{1}{2}\ in=(2+0.5)\ in=2.5\ in](https://tex.z-dn.net/?f=2%5C%20%5Cfrac%7B1%7D%7B2%7D%5C%20in%3D%282%2B0.5%29%5C%20in%3D2.5%5C%20in)
We know the scale drawing of the floor plan of Trinity's house is
, then, we need to multiply the dimensions of her living room on the floor plan by
in order to get the dimensions of her actual living room:
![(1.875\ in)(\frac{80}{1})=150\ in\\\\(2.5\ in)(\frac{80}{1})=200\ in](https://tex.z-dn.net/?f=%281.875%5C%20in%29%28%5Cfrac%7B80%7D%7B1%7D%29%3D150%5C%20in%5C%5C%5C%5C%282.5%5C%20in%29%28%5Cfrac%7B80%7D%7B1%7D%29%3D200%5C%20in)
Therefore, the dimensions of her actual living room are:
by ![200\ in](https://tex.z-dn.net/?f=200%5C%20in)
Because scientific notation has to be in between 1 and 10, you would need this to be 5.2. Count the spaces and since its getting smaller your exponent is negative.
Your answer should be 5.2*10^(-3)
Answer:
(a) 0.873 (b) 0.007 (c) 0.715 (d) 0.277 (e) 1.25 and 1.09
Step-by-step explanation:
The probability that the random variable X takes the value x is given by P(X=x) =
. Then,
(a) ![P(X\leq) = (25C0)(0.05^0)(0.95^{25}) + (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23})= 0.873](https://tex.z-dn.net/?f=P%28X%5Cleq%29%20%3D%20%2825C0%29%280.05%5E0%29%280.95%5E%7B25%7D%29%20%2B%20%2825C1%29%280.05%5E1%29%280.95%5E%7B24%7D%29%20%2B%20%2825C2%29%280.05%5E2%29%280.95%5E%7B23%7D%29%3D%20%200.873)
(b) ![P(X\geq5) = 1-P(X\leq4) = 1 - (0.873 + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21})) = 1 - (0.873 + 0.12) = 0.007](https://tex.z-dn.net/?f=P%28X%5Cgeq5%29%20%3D%201-P%28X%5Cleq4%29%20%3D%201%20-%20%280.873%20%2B%20%2825C3%29%280.05%5E3%29%280.95%5E%7B22%7D%29%20%2B%20%2825C4%29%280.05%5E4%29%280.95%5E%7B21%7D%29%29%20%3D%201%20-%20%280.873%20%2B%200.12%29%20%3D%200.007)
(c) ![P(1\leqX\leq4) = (25C1)(0.05^1)(0.95^{24}) + (25C2)(0.05^2)(0.95^{23}) + (25C3)(0.05^3)(0.95^{22}) + (25C4)(0.05^4)(0.95^{21}) = 0.715](https://tex.z-dn.net/?f=P%281%5CleqX%5Cleq4%29%20%3D%20%2825C1%29%280.05%5E1%29%280.95%5E%7B24%7D%29%20%2B%20%2825C2%29%280.05%5E2%29%280.95%5E%7B23%7D%29%20%2B%20%2825C3%29%280.05%5E3%29%280.95%5E%7B22%7D%29%20%2B%20%2825C4%29%280.05%5E4%29%280.95%5E%7B21%7D%29%20%3D%200.715)
(d)
(e) E(X) = np = (25)(0.05) = 1.25 and ![Sd(X) = \sqrt{Var(X)} = \sqrt{np(1-p)} = 1.09](https://tex.z-dn.net/?f=Sd%28X%29%20%3D%20%5Csqrt%7BVar%28X%29%7D%20%3D%20%5Csqrt%7Bnp%281-p%29%7D%20%3D%201.09)