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vfiekz [6]
3 years ago
13

Answer to all of this please!!! worth 50 points!!

Mathematics
2 answers:
qaws [65]3 years ago
4 0

A: (x^a) / (x^a) = x^(a - a) = x^0

B: Anything divided by itself is 1, so x^a / x^a = 1.

C: If x^a / x^a = x^0 from Part A and x^a / x^a = 1 from Part B, then x^0 = 1.

Reflect: 1. To complete Part A, we used the quotient rule for exponents.

Hope this helps!

Schach [20]3 years ago
4 0

Answer:

Step-by-step explanation:

A

\frac{x^{a} }{x^{a} }  = x^{a-a} =x^{0}

B

Anything divided by itself is 1, so \frac{x^{a} }{x^{a} } = 1

C

If \frac{x^{a} }{x^{a} } = x^{0} from part A, and \frac{x^{a} }{x^{a} } =1 from part B, then x^{0} = 1

Reflect:

Properties of exponents

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Step-by-step explanation:

<u>Step 1:  Find an equivalent to -3/8</u>

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Answer:

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4

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we are looking for the factors of 3, which are:

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List all possible combinations of ± \frac{p}{q}  as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3}

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