Question

PLEASE ANSWER CORRECTLY ASAP:

Answer 1

First one, subsitute x=-1 for x

$y=(x)^2-3(x)+12$
$y=(-1)^2-3(-1)+12$
$y=1+3+12$
$y=16$
so one solution is (-1,16)


2nd one, subsitute 2 for x

$y=(x)^2-3(x)+12$
$y=(2)^2-3(2)+12$
$y=4-6+12$
$y=10$
the second soltuion is (2,10)



so one solution is (-1,16)
the second solution is (2,10)