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Archy [21]
3 years ago
8

A certain 5-digit combination lock can be reset with a new combination. The lock uses numbers from 1 to 6. After a friend accide

ntally resets it to an unknown combination, what is the probability that you guess the combination that opens the lock
Mathematics
1 answer:
daser333 [38]3 years ago
5 0
The probability is (1/6)^5 power. Since the locks are independent of each other, you can multiply the probabilities together. There are 6 possible numbers for each lock and there are 5 locks. So the probability is (1/6)^5 power.<span />
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A college has a limited enrollment summer course that only accepts 50 students, selected at random from
Diano4ka-milaya [45]
The answer is 0.22 hope this helps
4 0
3 years ago
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Find the interest due on $600 at 9.5% for 120 days.
KATRIN_1 [288]

Answer:

Interest= $ 18.73

Step-by-step explanation:

Given : $600 at 9.5% for 120 days

To find : Find the interest due

Solution :

Simple interest formula  I=P\times r\times t

Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days

In years, 1 year = 365 days

1 day = \frac{1}{365} year

120 days = \frac{120}{365} year

Put values in the formula

I=P\times r\times t

I=600\times 0.095\times\frac{120}{365}

 I=\frac{6840}{365}=18.73

Therefore, Interest= $ 18.73




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3 years ago
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Can someone help plz
KIM [24]
I think the answer is B.
8 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
What is the rate of change for these numbers?
Snowcat [4.5K]
Wouldn't it be -1 (minus one)? 12 - 1 = 11 and 9 - 1 = 8.
8 0
3 years ago
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