Answer:
Assuming that you actually mean that if
is a factor of
, the answer is yes.
Step-by-step explanation:
We need to do long division of the polynomial to figure out if this is true. I would show it here, but it is extremely difficult to do so. (Maybe someone could help me.) When I factor it, it does not leave a remainder, so this is true.

Another way one could figure this out is by graphing the equation
on your graphing calculator or on just a graphing website, lake Desmos. The screenshot below shows the graph.
The polynomial will have a factor of
if the point
exists on the graph. The graph has the following three zeroes.
,
, and 
As such, it has the three factors
,
, and
.
Since
, it is a factor of the polynomial.