1. -6y
2. 4y+20
3. -6x+6y+4
4. 3x-44
5. •work:
•plug in 4 to the equation
5(2-4)=-10
10-20=-10
-10=-10
•so, yes it is a solution to 5(2-x)
6. •work:
4x+20=0
-20 -20
4x=-20
4x/4=-20/4
x=-5
7. •work:
5x-3=2x-27
-2x -2x
3x-3=-27
+3 +3
3x=-24
3x/3=-24/3
x=-8
8. •work:
6x-8=2x+16
-2x -2x
4x-8=16
+8 +8
4x=24
4x/4=24/4
x=6
9. •work:
12-3x=22+2x
-2x -2x
12-5x=22
-12 -12
-5x=10
-5x/-5=10/-5
x=-2
10. •work:
x+7x-12=-20
8x-12=-20
+12 +12
8x=-8
8x/8=-8/8
x=-1
11.•work:
7x+4-13x=-1+23
-6x+4=-1+23
-6x+4=22
-4 -4
-6x=18
-6x/-6=18/-6
x=3
here you go! hope this helped!! :)
What's the algebra question ?
The sum of the angles in a triangle is 180 degrees, so
x = 180 - 95 - 57 = 28°
Answer:
x^2 + 18x + 76 + 5 = 0 + 5
Step-by-step explanation:
The first step is to determine the constant that is needed to be able to write the expression in the desired form. That constant is the square of half the x-term coefficient: (18/2)^2 = 9^2 = 81.
The constant that is present is 76, which is 5 fewer than the needed constant, so the "first step" is to add 5 to both sides of the equation:
x^2 + 18x + 76 + 5 = 0 + 5
Then the next step would be to write the left side as a square:
(x +9)^2 = 5 . . . . . . . p = -9; q= 5
