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3 years ago

Which mixed number is greater than 4.63?

Mathematics

2 answers:

melomori [17]3 years ago

6 0

A because 4 2/3 are the greatest of all in the selection.

navik [9.2K]3 years ago

5 0

The answer is A, this is because
Number A would be 4.66
Number B would be 4.6
Number C would be 4.55
Number D would be 4.63

You would do this by 2/3 = 0.66 + 4 and your answer is 4.66. If you do this for all of them, you will be able to see all the results and which one fits it.

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En tu cuaderno realiza la conversión de los siguientes decimales a fracciones.<br>a) 0.250 :<br>

kenny6666 [7]

Answer:

Tengo que convertir los siguientes números decimales a fracciones, y también tengo que simplificarlos a su mínima expresión. Aquí un ejemplo ;)

(no pido que me digan las respuestas, si no que me ayuden a entenderla)

0.44 = 44/100 = 22/50 = 11/25

0.62=

0.29=

2.05=

1.28=

0.08=

0.50=

0.375=

0.60=

0.7=

Step-by-step explanation:

8 0

3 years ago

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I am having trouble graphing exponential functions. Can someone help me.

sertanlavr [38]

I can help tell me the problem

4 0

3 years ago

ILL BRAINLIEST YOU IF YOU GET IT RIGHT! Please help me

lara31 [8.8K]

Answer:

x = 25

Step-by-step explanation:

If JK and MN are parallel lines, then ∠JKL = ∠LMN = 61°

By the opposite angle rule, ∠JLK = 39°

In a triangle three angles sum up to 180°

so, ∠JLK + ∠JKL +LJK = 180°

39° + 61° + 3x+ 5 = 180°

3x = 75

x = 25

5 0

3 years ago

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Solve the system of equations below by graphing them with a pencil and paper. Enter your answer as an ordered pair.

sergejj [24]

Y = 2x - 3 . . . (1)
y = -2x + 5 . . . (2)
Equating (1) and (2),
2x - 3 = -2x + 5
2x + 2x = 5 + 3
4x = 8
x = 8/4 = 2
x = 2
y = 2(2) - 3 = 4 - 3 = 1
y = 1

Solution = (2, 1)

6 0

3 years ago

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Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

3 years ago