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A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point
Answer:
a)8.717km
b) 54.146°
Step-by-step explanation:
(a)how far is the boat from its starting point.
We solve this question using resultant vectors
= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)
Where
Rcos θ = x
Rsinθ = y
= (4cos38,4sin38) + (5cos67,5sin67)
= (3.152, 2.4626) + (1.9536, 4.6025)
= (5.1056, 7.065)
x = 5.1056
y = 7.065
Distance = √x² + y²
= √(5.1056²+ 7.065²)
= √75.98137636
= √8.7167296826
Approximately = 8.717 km
Therefore, the boat is 8.717km its starting point.
(b)calculate the bearing of the boat from its starting point.
The bearing of the boat is calculated using
tan θ = y/x
tan θ = 7.065/5.1056
θ = arc tan (7.065/5.1056)
= 54.145828196°
θ ≈ 54.146°
Answer:

Step-by-step explanation:
Answer:
180/147
Step-by-step explanation:
We need to find the additive inverse of the given numbers.
- For finding it we may simply out -1 as multiplication in front of the terms .
<u>SOLUTION</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u>
→ 3/-7 - 11/21
→ -3/7 -11/21
→ 3×-3 - 11 /21
→ -9-11/21
→ -20/21
<u>SOLUTION</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>
→ 9/5 ÷ 7/5
→ 9/5 × 5/7
→ 9/7
→ Product of nos . = -20/21 × -9/7
→ Ans = 180/147
50 miles per hour as they have been driving at a constant speed of 50 miles per hour throughout the trip.300/6=50 and 250/5=50
Answer:
I doo
Step-by-step explanation: