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Mumz [18]
2 years ago
8

Write an equation of the line passing through the given point and satisfying the given condition. Give the equation (a) in slope

-intercept form and (b) in standard form.
(8,6); perpendicular to 2x - y = 4
(a) Write the equation of the line in slope-intercept form.
Mathematics
1 answer:
kramer2 years ago
3 0

Answer:

y =  -\frac{1}{2}x + 10

Step-by-step explanation:

To find the equation of a line that passes through the point (8,6) and perpendicular to the equation 2x - y = 4, we will follow the steps below:

first write the equation 2x - y = 4 in a standard form

we will find the slope of our equation using this equation

2x - y = 4

y = 2x -4

comparing the above with

y = mx  + c

m = 2

m_{1}m_{2} = -1  ( slope of perpendicular equations)

2m_{2} = -1

m_{2}  = -1/2

our slope m = -1/2

We can now go ahead and form our equation

x_{1} =8   y_{1} =6

y-y_{1} = m (x-x_{1})

y-6 = -\frac{1}{2}(x-8)

y-6 =  -\frac{1}{2}x + 4

y=  -\frac{1}{2}x+4+6

y =  -\frac{1}{2}x + 10

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daser333 [38]

Answer:

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Here's how I got that:

<em>    - Group like terms -</em>

x - 2 + 2x + 4 + 2x - 2 = 180

                    ↓

      5x - 2 + 4 - 2 = 180

                    ↓

              5x = 180

<em>  - Divide both sides by 5 - </em>

<em>         </em>  5x/5 = 180/5

                   ↓

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<em>~ That's all folks ~</em>

<em>-Siascon</em>

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