Kyle's family bought 4 adult tickets and 2 student tickets for $52. Maria's family bought 3 adult tickets and 5 student tickets for $60. How much does each type of ticket cost?
1 answer:
Adult tickets cost $10 each and student tickets cost $6 each. Given: Kyle's family bought 4 adult tickets and 2 student tickets for $52 Maria's family bought 3 adult tickets and 5 student tickets for 60. Let us assign x as the adult tickets and y as the students tickets Kyle's family: 4x + 2y = 52 Maria's family: 3x + 5y = 60 Let us find the value of x using Kyle's equation: 4x + 2y = 52 4x = 52 - 2y x = (52 - 2y)/4 x = 13 - y/2 Substitute the value of x in Maria's equation to find y. 3x + 5y = 60 3(13 - y/2) + 5y = 60 39 - 3y/2 + 5y = 60 - 3y/2 + 5y = 60 - 39 - 3y/2 + 5y = 21 2(-3y/2 + 5y) = 2(21) -3y + 10y = 42 7y = 42 7y/7 = 42/7 y = 6 x = 13 - y/2 x = 13 - 6/2 x = 13 - 3 x = 10 To check: Kyle's Family Maria's Family 4x + 2y = 52 3x + 5y = 60 4(10) + 2(6) = 52 3(10) + 5(6) = 60 40 + 12 = 52 30 + 30 = 60 52 = 52 60 = 60
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