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mote1985 [20]
3 years ago
9

A 27-foot long wire is attached from a stake in the ground to the top of a 24-foot flagpole. Find the distance from the stake in

the ground to the flagpole. Round to the nearest tenth when necessary.
Mathematics
2 answers:
levacccp [35]3 years ago
6 0

Answer:

the distance is 3

Step-by-step explanation:

liraira [26]3 years ago
3 0

Answer:

12.4

Step-by-step explanation:

27^2=24^2+x^2

729=576+x^2

153=x^2

x=rt153

x=12.4

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Solve the system of linear equations by ellmination. 5x + 9y = -11 3x + 9y = -3 A. (-4,-1) -B. (-1, –4) C. (-4,1) D. (1,-4)​
valentina_108 [34]

Answer:

Step-by-step explanation:

5x + 9y = -11

3x + 9y  = -3

5x + 9y = -11

-3x - 9y = 3

2x = -8

x = -4

-12 + 9y = -3

9y = 9

y = 1

(-4, 1)

Answer is C

5 0
3 years ago
HELP ASAP PLEASE!!!!!!!!!!!
Inessa05 [86]

Look in the table at the column that has 1 minute and 4.25 pages. Printer A prints 4.25 pages in 1 minute which is a rate of 4.25 pages per minute. The rate of printing is the slope in the equation. A rate of 4.25 pages per minute is represented by the equation y = 4.25x, where 4.25 ids the slope of the equation.

We are told that Printer A prints faster than Printer B, so Printer B must have a lower rate of printing than Printer A. The equation for Printer B must have a slope less than 4.25.

There are two choices which have a slope less than than 4.25.

Answer: y = 4.2x; y = 4x

3 0
3 years ago
A cupcake shop uses 1/3 pounds of cinnamon to make 4 batches. How much do they use per batch?
tiny-mole [99]
1/12 of a pound.
you must use the reciprocal of 4, 1/4, then multiply. so 1/3*1/4= 1/12
5 0
3 years ago
Read 2 more answers
Good evening, I am taking an Algebra class for the first time after 50 years, and can not remember how to find the point-slope f
Olin [163]
m=-1/5p x 10.4
m=-1/5p x 52/5
m=-52/25p

8 0
3 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
3 years ago
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