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2 years ago

Write the ordered pair that represents yz. Then find the magnitude of yz . y=14,-23 z=23,-14

Mathematics

2 answers:

Firlakuza [10]2 years ago

4 0

Answer:

Ordered pair of yz is ( 9 , 9 ) and Magnitude of yz is 9√2 unit.

Step-by-step explanation:

Given ordered pair of y and z are ( 14 , -23 ) and ( 23 , -14 ) respectively

To find: Ordered pair of yz and magnitude of yz

To find order pair of yz we subtract ordered pair of y from z.

Ordered pair of yz = ( 23 - 14 , -14 - (-23) )

= ( 9 , -14 + 23 )

= ( 9 , 9 )

Magnitude of yz , $[\left|yz\right|\:=\:\sqrt{9^2+9^2}$

= $\sqrt{81+81}$

= $\sqrt{2\times81}$

= $9\sqrt{2}$

Therefore, Ordered pair of yz is ( 9 , 9 ) and Magnitude of yz is 9√2 unit.

N76 [4]2 years ago

4 0

Answer:

A on e2020

Step-by-step explanation:

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Find the values for a and b that would make the equality true.

Crank

Answer:

a = - 4, b = 5

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on the right side.

- 3(2x² + ax + b)

= - 6x² - 3ax - 3b

Comparing like terms with - 6x² + 12x - 15

x - term → - 3a = 12 ( divide both sides by - 3 )

a = - 4

constant term → - 3b = - 15 ( divide both sides by - 3 )

b = 5

6 0

3 years ago

HELP ME PLEASE!!

DiKsa [7]

C=A+B
C₄₁= row=4; column=1
C₄₁=A₄₁+B₄₁
=2(7)-3(4)
=14-12
=2

Answer: C₄₁=2

5 0

2 years ago

The following stem-and-leaf plot shows the on-record attendance for regional charity drive meetings.

yaroslaw [1]

I’ll answer when I get home

4 0

2 years ago

Find the exact value of tan (arcsin (two fifths)). For full credit, explain your reasoning.

Hitman42 [59]

$\bf sin^{-1}(some\ value)=\theta \impliedby \textit{this simply means}
\\\\\\
sin(\theta )=some\ value\qquad \textit{now, also bear in mind that}
\\\\\\
sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad 
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\$

$\bf sin^{-1}\left( \frac{2}{5} \right)=\theta \impliedby \textit{this simply means that}
\\\\\\
sin(\theta )=\cfrac{2}{5}\cfrac{\leftarrow opposite}{\leftarrow hypotenuse}\qquad \textit{now let's find the adjacent side}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm \sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a
\\\\\\
\textit{we don't know if it's +/-, so we'll assume is the + one}\quad \sqrt{21}=a\\\\
-------------------------------\\\\
tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(\theta)=\cfrac{2}{\sqrt{21}}
\\\\\\
\textit{and now, let's rationalize the denominator}
\\\\\\
\cfrac{2}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{(\sqrt{21})^2}\implies \cfrac{2\sqrt{21}}{21}
$

7 0

2 years ago

19 + 11 - 12² ÷ 3 (12 - 9) · 11)) - 7 =

katovenus [111]

PEMDAS = Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

First, subtract the numbers in the parentheses, then multiply by 11.

(12 - 9) = (3)

3 x 11 = 33

19 + 11 - 12^2 ÷ 3(33) - 7

Now, just multiply 33 by 3, and then square 12 (12 x 12).

19 + 11 - 144 ÷ 99 - 7

Now, you can divide 144 by 99, this is an infinite number, so..

144 ÷ 99 = 1.455

19 + 11 - 1.455 - 7

Finally add, then subtract.

30 - 1.455 - 7

28.545 - 7

The final answer is 21.545.

7 0

2 years ago