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3 years ago

Write the ordered pair that represents yz. Then find the magnitude of yz . y=14,-23 z=23,-14

Mathematics

2 answers:

Firlakuza [10]3 years ago

4 0

Answer:

Ordered pair of yz is ( 9 , 9 ) and Magnitude of yz is 9√2 unit.

Step-by-step explanation:

Given ordered pair of y and z are ( 14 , -23 ) and ( 23 , -14 ) respectively

To find: Ordered pair of yz and magnitude of yz

To find order pair of yz we subtract ordered pair of y from z.

Ordered pair of yz = ( 23 - 14 , -14 - (-23) )

= ( 9 , -14 + 23 )

= ( 9 , 9 )

Magnitude of yz , $[\left|yz\right|\:=\:\sqrt{9^2+9^2}$

= $\sqrt{81+81}$

= $\sqrt{2\times81}$

= $9\sqrt{2}$

Therefore, Ordered pair of yz is ( 9 , 9 ) and Magnitude of yz is 9√2 unit.

N76 [4]3 years ago

4 0

Answer:

A on e2020

Step-by-step explanation:

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1 year ago

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luda_lava [24]

Formula: A = pq/2

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Substitute with the given values and solve.

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3 0

3 years ago

Match the following rational expressions to their rewritten forms.

Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

$1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}$

And the rewritten forms:

$(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}$

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

$(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}$

So, correct option is 3.

$(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}$

So, correct option is 1.

$(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}$

So, correct option is 2.

$(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}$

So, correct option is 4.

The answer is also attached in the answer area.

7 0

2 years ago

Please help if you can:)

Zepler [3.9K]

87.41898806% or 87% is what i got

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3 years ago