Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
1
Step-by-step explanation:
We need two points to find the slope
( -1,0) and ( 2,3)
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 3-0)/(2 - -1)
= (3-0) / ( 2+1)
= 3/3
= 1
The slope is 1
Given:
Sum of interior angle
To find:
Number of sides of a polygon
Solution:
Using sum of interior angles formula:
where "S" is the sum of interior angels and "n" is the number of sides of a polygon.
Divide by 180° on both sides.
Cancel common factor 180°.
Add 2 on both sides.
Switch the sides.
Therefore number of sides of a polygon is 
.
?
Step-by-step explanation:
3/5 ÷ 10/11
multiply by the inverse
3/5 x 11/10 = 33/50
