Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
I believe it's 3/10 but I'm not confident about that.
Step-by-step explanation:
Set up the composite result function.
f(g(x))f(g(x))
Evaluate f(g(x))f(g(x)) by substituting in the value of gg into ff.
f(x2)=2(x2)−4f(x2)=2(x2)-4
Multiply 22 by x2x2.
f(x2)=2x2−4f(x2)=2x2-4
The answer is 64!!
Hope this helps!
