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Fofino [41]
4 years ago
10

I need help ASAP I have to turn this in 2 minutes.

Mathematics
1 answer:
kondor19780726 [428]4 years ago
6 0
It is J. i hope it helps
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Which expression is equivalent to
sweet-ann [11.9K]

Answer:

ITS D  ITS NOT THERE

Step-by-step explanation:

7 0
3 years ago
10. Both x and y vary inversely with each other. When x is 10, y is 6,which of the following is not a possible pair of correspon
elena55 [62]

9514 1404 393

Answer:

  D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

  y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

  xy = k . . . . . . multiply the above equation by x

  (10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

  y = 60/x

you can multiply them together to see if the product is 60.

  (A) 12×5 = 60

  (B) 15×4 = 60

  (C) 25×2.4 = 60

  (D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

8 0
3 years ago
A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60
Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let c(t) is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt

\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0

\int\limits^{20}_{0} {c'(t)} \, dt =3600+600

\int\limits^{20}_{0} {c'(t)} \, dt =4200

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0
3 years ago
Help on how to figure this out
MakcuM [25]
6/3 = 6 divided by 3
= 2

12/6= 12 divided by 6
= 2

3 0
3 years ago
A 90-kg astronaut biologist searches for microbial life on Mars where the gravitational acceleration is g = 3.71 m/s2. What is t
Yuki888 [10]
M = 90 kg,
On Mars:  g = 3.71 m/s² 
Weight = m · g = 90 kg · 3.71 m/s² = 333.9 N
1 N = 0.2248 lbf
333.9 · 0.2248 = 75.06072 lbf ≈ 75 lbf
5 0
3 years ago
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