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jekas [21]
3 years ago
10

I need help on this problem please ?

Mathematics
2 answers:
MrRa [10]3 years ago
7 0
The answer to this answer is B
marishachu [46]3 years ago
4 0
Use L'Hopital's Rule.
Since substituting pi into the equation renders 0/0, we need to take the derivative of both, the numerator and denominator and then using the limits again.

\lim_{x \to \pi} (\frac{-sinx + 2cos(2x)}{2x})
Now, substituting pi into the equation renders \frac{0 + 2}{2\pi}

So, our limit becomes \frac{1}{\pi} (ie B)
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