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Elis [28]
2 years ago
7

Kindly answer the first question . LCM of 20,35 and 30​

Mathematics
1 answer:
lukranit [14]2 years ago
3 0

<em>R</em><em>e</em><em>f</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>t</em><em>t</em><em>a</em><em>c</em><em>h</em><em>m</em><em>e</em><em>n</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em> </em><em>s</em><em>o</em><em>u</em><em>l</em><em>t</em><em>i</em><em>o</em><em>n</em><em>!</em><em>!</em><em> </em>:)

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Answer:

n= -4

Step-by-step explanation:

First we have to find the equation of line which passes through (6,3) and (8,4).

Then we have to pass this line through the point (n , -2).

we know, equation of line passing through (x1,y1) and (x2,y2) is

\frac{x-x1}{x1-x2}=\frac{y-y1}{y1-y2}

So, the equation of line passing through (6,3) and (8,4) is

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or, \frac{x-6}{-2} =\frac{y-3}{-1}

multiplying both sides by  -2

x-6=2(y-3)

or, x-6=2y-6

or, x-2y=6-6

or, x-2y=0


Now, we have to pass this line through  (n,-2)

So, using the point in the line, that is using  x=n  , y=-2

we get

n-2(-2)=0

or, n+4=0

or, n=-4

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