<span>Minimum wykresu funkcji kwadratowej znajduje się w ( -1, 2). Punkt ( 2 , 20) jest również od paraboli. Która funkcja reprezentuje sytuację?
</span><span>Canonical form of the function
</span>f(x) = a* (x - p)² + q
A .f(x) = (x + 1)² + 2 ⇔ p= -1 , q = 2
B. f(x) = (x – 1)² + 2 we reject
C. f(x) = 2(x + 1)² + 2 ⇔ p = -1 , q = 2
D .f(x) = 2(x – 1)² + 2 we reject
The point (2,20) substitute
A f(x) = (x +1)² + 2
20 = (2 + 1 )² + 2
20 ≠ 9 +2
20 ≠ 11 we reject
D f(x) = 2* (x + 1)² + 2
20 = 2* (2+1)² + 2
20 = 2 * 3² + 2
20 = 2 * 9 + 2
20 = 18 + 2
Reply C
Answer:
Step-by-step explanation:so I think
You +8×5=40
-4×3=-12
800 is linear and 500 is exponential
Answer:
b
Step-by-step explanation:
9514 1404 393
Answer:
Molly
Step-by-step explanation:
Brady did not properly create a square.
The square of a binomial is ...
(a -b)² = a² -2ab +b²
Where a²=x² and -2ab = -4x, you find b=2. The constant term in the square is 2²=4. Brady shows it as -4, which is incorrect.
Molly's work is correct.
